Exercise 6 feedback

$\begin{align*} L_{1}:y=&2x+3\\ L_{2}:y=&-2x+4\\ L_{3}:y=&-\frac{1}{2}+3\\ L_{4}:y=&x+3\\ \end{align*}$

Line	$L_{1}$	$L_{2}$	$L_{3}$	$L_{4}$
Slope			$-\frac{1}{2}$

1.	Since the slopes are all different, none of the lines are parallel.
2.	Since the product of Slope(L₁) and Slope(L₃) is -1, L₁and L₃ are perpendicular.

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