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The number of different ways to display the 5 brands of sweets in 3 spaces is

$\begin{align*} P(5,\:3)=&\frac{5!}{(5-3)!}\\ =&\frac{5!}{2!}=60\\ \end{align*}$

The number of different ways to display the 5 brands of sweets in 3 spaces is

$\begin{align*} P(5,\:3)&=\frac{5!}{(5-3)!}\\ &=\frac{5!}{2!}=60\\ \end{align*}$

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