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Catching exceptions

8 September, 2015 - 10:43

A lot of things can go wrong when you try to read and write files. If you try to open a file that doesn’t exist, you get an IOError:

>>> fin = open('bad_file')IOError: [Errno 2] No such file or directory: 'bad_file'

If you don’t have permission to access a file:

>>> fout = open('/etc/passwd', 'w')IOError: [Errno 13] Permission denied: '/etc/passwd'

And if you try to open a directory for reading, you get

>>> fin = open('/home')IOError: [Errno 21] Is a directory

To avoid these errors, you could use functions like os.path.exists and os.path.isfile, but it would take a lot of time and code to check all the possibilities (if “Errno 21” is any indication, there are at least 21 things that can go wrong).

It is better to go ahead and try—and deal with problems if they happen—which is exactly what the try statement does. The syntax is similar to an if statement:

try:fin = open('bad_file')for line in fin:print linefin.close()except:print 'Something went wrong.'

Python starts by executing the try clause. If all goes well, it skips the except clause and proceeds. If an exception occurs, it jumps out of the try clause and executes the except clause.

Handling an exception with a try statement is called catching an exception. In this example, the except clause prints an error message that is not very helpful. In general, catching an exception gives you a chance to fix the problem, or try again, or at least end the program gracefully.

Exercise 14.2.Write a function called sedthat takes as arguments a pattern string, a replacementstring, and two filenames; it should read the first file and write the contents into the second file(creating it if necessary). If the pattern string appears anywhere in the file, it should be replacedwith the replacement string.

If an error occurs while opening, reading, writing or closing files, your program should catch theexception, print an error message, and exit. Solution: http: // thinkpython. com/ code/ .