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- Bandwidth of HF = (30 – 3) MHz = 27 MHz; Frequency band for each user = 27 MHz / 150 users = 0.18 MHz each
- Let n be the number of users and there would be n – 1 frequency gaps in between. Then, 2000 n + 100 (n - 1) ≤ 200 × 103→ n≤ 95.29. The maximum number of users is 95.
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