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Solution to Exercise 4.3

9 October, 2015 - 14:47
% This script computes the load carried by the larger piston in a hydraulic system 
clc                         % Clear screen
disp('This script computes the load carried by the larger piston in a hydraulic system') 
disp(' ')                   % Display blank line
initialF=150;
finalF=200;
increment=10;
area1=25; 
area2=100; 
F1=[initialF:increment:finalF]; % Creating a row vector with F1 values 
F2=F1*area2/area1; % Calculating F2 values 
disp(' ')                   % Display blank line 
str = [' F1 F2 '];% Displaying table header 
disp(str); 
disp([F1' F2']) % Tabulating results in two columns, ' is being used to transpose row to column 

The script output is as follows:

This script computes the load carried by the larger piston in a hydraulic system

F1  F2
150 600
160 640
170 680
180 720
190 760
200 800