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To demonstrate how the interp1 function works, let us create an x-y table with the following commands;
x = 0:5; y = [0,20,60,68,77,110];
To tabulate the output, we can use
[x',y']
The result is
ans =
0 0
1 20
2 60
3 68
4 77
5 110
Suppose we want to find the corresponding value for 1.5 or interpolate for 1.5. Using y new = interp1(x,Y,x new) syntax, let us type in:
y_new=interp1(x,y,1.5)
y_new =
40
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