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To demonstrate how the interp1 function works, let us create an x-y table with the following commands;
x = 0:5; y = [0,20,60,68,77,110];
To tabulate the output, we can use
[x',y']
The result is
ans = 0 0 1 20 2 60 3 68 4 77 5 110
Suppose we want to find the corresponding value for 1.5 or interpolate for 1.5. Using y new = interp1(x,Y,x new) syntax, let us type in:
y_new=interp1(x,y,1.5) y_new = 40
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