Available under Creative Commons-ShareAlike 4.0 International License.
MATLAB solution is as follows:
» new_temperature=25:5:150;
» new_specific_heat=interp1(temperature,specific_heat,new_temperature);
» [new_temperature',new_specific_heat']
ans =
25.0000 0.1180
30.0000 0.1184
35.0000 0.1188
40.0000 0.1192
45.0000 0.1196
50.0000 0.1200
55.0000 0.1206
60.0000 0.1212
65.0000 0.1218
70.0000 0.1224
75.0000 0.1230
80.0000 0.1234
85.0000 0.1238
90.0000 0.1242
95.0000 0.1246
100.0000 0.1250
105.0000 0.1256
110.0000 0.1262
115.0000 0.1268
120.0000 0.1274
125.0000 0.1280
130.0000 0.1286
135.0000 0.1292
140.0000 0.1298
145.0000 0.1304
150.0000 0.1310
- 瀏覽次數：2148
