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MATLAB solution is as follows:
» new_temperature=25:5:150; » new_specific_heat=interp1(temperature,specific_heat,new_temperature); » [new_temperature',new_specific_heat'] ans = 25.0000 0.1180 30.0000 0.1184 35.0000 0.1188 40.0000 0.1192 45.0000 0.1196 50.0000 0.1200 55.0000 0.1206 60.0000 0.1212 65.0000 0.1218 70.0000 0.1224 75.0000 0.1230 80.0000 0.1234 85.0000 0.1238 90.0000 0.1242 95.0000 0.1246 100.0000 0.1250 105.0000 0.1256 110.0000 0.1262 115.0000 0.1268 120.0000 0.1274 125.0000 0.1280 130.0000 0.1286 135.0000 0.1292 140.0000 0.1298 145.0000 0.1304 150.0000 0.1310
- 瀏覽次數:1589