
Using the table below, find the internal energy of steam at 215 ˚C and the temperature if the internal energy is 2600 kJ/kg (use linear interpolation).
Temperature [C] |
Internal Energy [kJ/kg] |
100 |
2506.7 |
150 |
2582.8 |
200 |
2658.1 |
250 |
2733.7 |
300 |
2810.4 |
400 |
2967.9 |
500 |
3131.6 |
First let us enter the temperature and energy values
temperature = [100, 150, 200, 250, 300, 400, 500]; energy = [2506.7, 2582.8, 2658.1, 2733.7, 2810.4, 2967.9, 3131.6]; [temperature',energy']
returns
ans = 1.0e+003 * 0.1000 2.5067 0.1500 2.5828 0.2000 2.6581 0.2500 2.7337 0.3000 2.8104 0.4000 2.9679 0.5000 3.1316
issue the following for the first question:
new_energy = interp1(temperature,energy,215)
returns
new_energy = 2.6808e+003
Now, type in the following for the second question:
new_temperature = interp1(energy,temperature,2600)
returns
new_temperature = 161.4210
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