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A derivative

20 一月, 2016 - 10:05

That proves that \dot{x}(1)=1, but it was a lot of work, and we don't want to do that much work to evaluate \dot{x} at every value of t. There's a way to avoid all that, and find a formula for \dot{x} . Compare Figure 1.8 and Figure 1.10. They're both graphs of the same function, and they both look the same. What's different? The only difference is the scales: in Figure 1.10, the t axis has been shrunk by a factor of 2, and the x axis by a factor of 4. The graph looks the same, because doubling t quadruples t^2/2. The tangent line here is the tangent line at t=2, not t=1, and although it looks like the same line as the one in Figure 1.8, it isn't, because the scales are different. The line in Figure 1.8 had a slope of rise/run = 1/1 = 1, but this one's slope is 4/2 = 2. That means \dot{x}(2)=2. In general, this scaling argument shows that \dot{x}(t)=t for any t.

media/image10.png
Figure 1.10
The function 
 
t^2/2 again. How is this different from Figure 1.8?

This is called differentiating: finding a formula for the function \dot{x} , given a formula for the function x. The term comes from the idea that for a discrete function, the slope is the difference between two successive values of the function.

The function \dot{x} is referred to as the derivative of the function x, and the art of differentiating is differential calculus. The opposite process, computing a formula for x when given \dot{x}, is called integrating, and makes up the field of integral calculus; this terminology is based on the idea that computing a running sum is like putting together (integrating) many little pieces.

Note the similarity between this result for continuous functions,

\begin{matrix} x=t^2/2 & \dot{x}=t \end{matrix}

and our earlier result for discrete ones,

\begin{matrix} x=(n^2+n)/2 & \dot{x}=n \end{matrix}

The similarity is no coincidence. A continuous function is just a smoothed-out version of a discrete one. For instance, the continuous version of the staircase function shown in Figure 1.2 would simply be a triangle without the saw teeth sticking out; the area of those ugly sawteeth is what's represented by the n/2 term in the discrete result x=(n^2+n)/2, which is the only thing that makes it different from the continuous result x=t^2/2.