Solutions for chapter 6

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The method of nding the inde nite integral is discussed in example 70 on p. 91 and problem 16 on p. 99. The result is $-(In2)^{-3}e^{-u}(-u^{2}-2u+2)$ , where u = -x In 2. Plugging in the limits of integration, we obtain $2(In2)^{-3}$ .

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Solutions for chapter 6