You are here

Euler's Formula

4 June, 2015 - 15:31

Surprisingly, the polar form of a complex number z can be expressed mathematically asz = re^{j\theta }

To show this result, we use Euler's relations that express exponentials with imaginary arguments in terms of trigonometric functions.

e^{j\theta}=cos(\theta)+jsin(\theta)
cos(\theta)=\frac{e^{j\theta}+e^{-(j\theta)}}{2}
sin(\theta)=\frac{e^{j\theta}-e^{-(j\theta)}}{2j}

The first of these is easily derived from the Taylor's series for the exponential.

e^{x}=1+\frac{x}{1!}+\frac{x^2}{2!}+\frac{x^3}{3!}+...

Substituting jθ for x, we find that

e^{j\theta}=1+j\frac{\theta}{1!}-\frac{\theta^2}{2!}-j\frac{\theta^3}{3!}+...

because j2 = −1, j3 = −j, and j4 =1. Grouping separately the real-valued terms and the imaginary-valued ones,

e^{j\theta}=1-\frac{\theta^2}{2!}+...+j(\frac{\theta}{1!}-\frac{\theta^3}{3!}+...)

The real-valued terms correspond to the Taylor's series for cos (θ), the imaginary ones to sin (θ), and Euler's first relation results. The remaining relations are easily derived from the first. We see that multiplying the exponential in (2.3) by a real constant corresponds to setting the radius of the complex number to the constant.